Which of the following is true? I has a higher boiling point, than II because of

Question

Which of the following is true? I has a higher boiling point, than II because of stronger intermolecular interaction in I I has a higher boiling point, than II because of weaker intermolecular interaction in I I has a lower boiling point, than II because of weaker intermolecular interaction in I I has a lower boiling point, than II because of weaker intermolecular interaction in I I has a lower boiling point, than II because of higher stability of II What is the following reaction step? Shared first step of E1 and S_N1 Second step of alkene hydration Shared second step of hydration of propene and hydrohalogenation of propene Shared first step of hydration of propene and hydrobromination of propene First step of alkence bromination Reactivity in the S_N1 reaction decreases in the following order: 1-Chloropropane >2-Chloropropane > 2-Chloro-2-methylpropane.'' What is your opinion about this statement? True, because the steric hindrance increases in this order False, because stability of the carbocation increases in this order True, because the leaving group is involved in the rate-limiting step True, because stability of the final product increases in this order False, because nucleophilicity increases in this order

Explanation / Answer

I is linear vs. II branched

there are higher interacitons in linear molecules than branched, so expect higher boiling points in linear alkanes

so...

ignore C,D,E

Only A makes sense, since higher interactions will have higher BP

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