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How many milliliters of 0.132 M HCIO_4 solution are needed to neutralize 50.00 m

ID: 1070182 • Letter: H

Question

How many milliliters of 0.132 M HCIO_4 solution are needed to neutralize 50.00 ml of 0.0789 M NaOH? 0.521 0.0120 83.7 0.0335 29.9 Silver ions can be precipitated from aqueous solutions by the addition of aqueous chloride: Ag^+ (aq) + Cl^- (aq) rightarrow AgCI(s) Silver chloride is virtually insoluble in water so that the reaction appears to go to completion. How many grams of solid NaCI must be added to 25.0 ml of 0.366 M AgNO_3 solution to completely precipitate the silver? 9.15 times 10^-3 g 1.57 times 10^-4 g 0.535 g 0.157 g 6.39 times 10^3 g What reagent could be used to separate Br^- from CH_3CO_2- when added to an aqueous solution containing both? AgNO_3(aq) Ba(OH)_2(aq) CuSO_4(aq) Nal(aq) Based on the balanced chemical equation shown below, determine the mass percent of Fe^3+ in a 0.7450 g sample of iron ore, if 22.40 ml of a 0.1000 M stannous chloride, SnCl_2(aq). solution is required to completely react with the Fe^3+ present in the ore sample. The chemical equation for the reaction is Fe^3+(aq) + Sn^2+(aq) rightarrow 2 Fe^2+(aq) + Sn^4+(aq). 5.365% 8.396% 16.79% 33.58%

Explanation / Answer

11. ml of HClO4 needed

= 0.0789 M x 50 ml/0.132 M

Answer : E) 29.9 ml

12. grams of NaCl required for precipitation

= 0.366 M x 0.025 L x 58.44 g/mol

Answer : C) 0.535 g

13. To separate Br- and CH3CO2-, we would use,

A) AgNO3

AgBr is insoluble solid and CH3COOAg is soluble.

14. Mass of Fe3+ in ore = 0.1 M x 0.02240 L x 55.845 g/mol = 0.1251 g

mass% Fe3+ = 0.1251 x 100/0.7450

Answer : C) 16.79%

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