Write a nuclear equation for the alpha decay of Pa_91^231 Write a nuclear equati

Question

Write a nuclear equation for the alpha decay of Pa_91^231 Write a nuclear equation for the beta decay of Fr_87^223 Write a nuclear equation for the alpha decay of Sm_62^149 Write a nuclear equation for the beta decay of Pm_61^565 Write a nuclear equation for the alpha decay of Md_101^249 Write a nuclear equation for the alpha decay of Sm_62^144 Write a nuclear equation for the beta decay of At_85^196 Write a nuclear equation for the alpha decay of Gd_54^152 Write a nuclear equation for the beta decay of Xe_54^152 Write a nuclear equation for the beta decay of Cs_55^120

Explanation / Answer

alpha is noting but helium nucleus. Hence

X is actinium. There is a balance of atomic number (91--->2+89) and mass number ( 231--->4+227)

2.

beta decay is release of electrons. As a results, there is an increase in atomic number by 1.

3.

Nd is neodymium

4.

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