can someone explain how to solve for k p assuming this datat F( ) 295 301 305 31
ID: 1070610 • Letter: C
Question
can someone explain how to solve for kp assuming this datat
F() 295 301 305 311 315 319 332.5 337.5 342.5 347.5 352.5 357.5 362.5 372.5 377.5 382.5 387.5 392.5 397.5 402.5 407.5 412.5 0 0.01 0.09 0.61 1.13 1.7 10.22 10.14 11.12 11.33 13.09 11.84 13.23 1.48 1.69 1.44 1.59 1.6 1.97 2.74 2.68 2.8 11.54 13.44 15.89 18.67 24.53 24.77 34.25 37.98 37.98 40.65 43.13 47.17 48.33 53.15 55.08 56.44 59.27 58.45 60.21 57.81 59.99 56.51 0.998 0.997 0.996 0.995 0.994 0.993 0.991 0.99 0.98 0.988 0.987 0.946 0.984 0.981 0.979 0.975 0.996 0.957 0.87 0.56 0.225 0.094Explanation / Answer
Just multiply F()()() at each and add all those values,
At = 295 , KP = 0.998*11.54*0 = 0
At = 301 , KP = 0.997*13.44*0.997 = 0.133996
At = 305 , KP = 0.996*15.89* 0.09 = 13.346081
At = 311, KP = 0.995*18.67*0.61 = 11.3317565
At = 315, KP = 0.994*24.53*1.13 = 27.5525866
At = 319, KP = 0.993*24.77*1.7 = 41.814237
At = 332.5 , KP = 0.991*34.25*10.22 = 346.884685
At = 337.5 , KP = 0.99*37.98*11.12 = 418.114224
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At = 412.5 , KP = 0.094*56.51*2.8 = 14.873432
Just add all these values, to get KP
KP = 4067.92366
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