In an S_N2 reaction, the effect of doubling both nucleophile and substrate conce
ID: 1070786 • Letter: I
Question
In an S_N2 reaction, the effect of doubling both nucleophile and substrate concentration at the same time is to multiply the reaction rate by: the chloride that reacts the fastest with NaOH is What is the major product of the reaction Which energy-reaction coordinates diagram represents this reaction? The major product of this reaction is Which compound would be most rapidly hydrolyzed by aqueous HCl to give methanol as one of the products? CH_2OCH_2CH_2CH_3 CH_2OCH_2CH_2CH_2OCH_3 CH_3OCH_2CH_2OH Which intermediate is involved in this reaction: Addition of bromine to (E)-3-hexene will give one meso compound one pair of enantiomers. two meso compounds four streoisomers.Explanation / Answer
33) In SN2 reaction, rate depends on both reactant and nucleophile so doubling the concn of both will increase to 4 fold. so nswer is D
34) Answer D. Due to electron withdrawing effect at ortho and para poition attack of OH- become easy and possible.
35) Answer C. Arrange the str. for anti elimination. You will get H and Br anti to each other which make two phenyl ring trans to each other.
36) Answer D. It is a SN1 two step reaction proceeding through carbocation.
37) Answer A. Elimination reaction forms more substituted as major product.
38) D becuse the resulting carbocation cn be stabilized by electron donating oxygen.
39) B. It is a benzyne intermediate reaction.
40) A because addition of Br2 to trans alkene give single meso compound.
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