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How many fmols and microliters do I need, given this information? Really need he

ID: 1071547 • Letter: H

Question

How many fmols and microliters do I need, given this information? Really need help with this one!

Info:

-mw=660 * number of base pairs

-mols=g/mw

-Sample A has 2958 base pairs

-Sample B has 815 base pairs

-The reaction requires a 3:1 A:B ratio

How much B (in fmols AND in microliters) do you need if you use 1 microliter of 50 ng/microliter of A.

Here is a table that may help: the ?? is something that must be decided and inserted!

please show work

B: fmol/o fmol of B A: mol/o Fmol of A Microliter Microliter of A of B

Explanation / Answer

Molecular weights : A = 2958*660 =1952280,   B= 815*660=537900

Mass of A= 50*10-9 g/microliter*1 = 50*10-9 gm

Moles of A = 50*10-9/1952280 =2.56*10-14

A :B =3:1

A/B= 3/1

A= 3B or B=A/3

Moles of B= 2.56*10-14/3= 8.5*10-15 moles= 8.5 fmoles

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