The equivalent of 10 cm^3 is 0.010 L 100 mm^3 10 ml 0.10 L 0.0010 L The number o

Question

The equivalent of 10 cm^3 is 0.010 L 100 mm^3 10 ml 0.10 L 0.0010 L The number of grains equivalent to 1.5 moles of lead (II) oxide 215 305 131 279 335 The number of grams in 4.55 times 10^16 molecules of carbon dioxide is 19.3 3.33 times 10^-6 1.97 times 10^-3 291 1.44 times 10^-4 "Nano" means 10^-6 10^-9 10^6 10^3 10^-3 In the balanced reaction between barium oxide and aluminum to form aluminum oxide and barium, the coefficient in front of barium is 1 2 3 4 5 The equivalent of 2.51 pounds is 6.88 times 10^2 g 24.4 g 1.14 times 10^3 g 1.56 g 8.33 times 10^2 g SO is an example of a(n) cation anion ionic compound base covalent compound The equivalent of 22degree C is -251K 14 degree F 259 K 295 K -22 degree F A density of 1.2 g/ml is equivalent to 2.6 times 10^-3 lb/cm^3 6.8 lb/ml 1.5 times 10^-4 Ib/L 8.31b/L 1.2 mg/L

Explanation / Answer

Question 1

the equivalent of 10cm^3 is

10 cm^3 = 0.01 litre---------answer

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Question 2

The number of grams equivalent to 1.5 moles of lead (II) oxide

Answer d) 335 grams-------------answer

1.5 moles of lead (II) oxide =334.7991 grams

molecular weight of Lead(II) Oxide or grams
The molecular formula for Lead(II) Oxide is PbO.
The SI base unit for amount of substance is the mole.
1 mole is equal to 1 moles Lead(II) Oxide, or 223.1994 grams.

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Question 3

The number of grams in 4.55 x10^16 molecules of carbon dioxide is

mass of 1 mole carbon dioxide =44.01 g/mol ----- -= 6.023 x10^23 molecules

-----------------------------------------------------------x grams-------------------4.55 x10^16 molecules

= (4.55 x10^16 molecules /6.023 x10^23 molecules) 44.01 g/mol

= (4.55 / 6.023) 44.01 = 3.33 x10^-6-----------------answer

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Question 4

4) Nano means

b)10^-9-answer

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Question 5

In the balanced reaction between barium oxide and aluminium to form aluminium oxide and barium

3 BaO + 2 Al = 3 Ba + Al2O3

answer c) 3 ---------------answer

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Question 6

The equivalent of 2.51 pounds is

c) 1.14 x10^3

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Question 7

SO is an example of

e) covalent compound

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Question 8

The equivalent of 22c

22+273=295 k------answer

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Question 9

A density of 1.2 g/ml is equivalent

a) 0.00264555 =2. X10^-3 lb/cm^3 -----------answer

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