The answer is e my calculations seem to be close but I\'m just not getting an ex

Question

The answer is e my calculations seem to be close but I'm just not getting an exact number that correlates with the correct percentage for each isotope please help. Vanadium is commonly found as an additive to steel to strengthen the metal. There are only two 5. major isotopes of vanadium found in nature, 50V and siv. What is the approximate abundance of each isotope in a natural sample of vanadium? Hint: calculator not required. >90%, 50 and 10% siv. b, 25% 107 and 75% 109 c. 50% 107 and 50% 109 V d. 75%, 107v and 25% 109 e. 10% 50 and 90% 51

Explanation / Answer

average atomicmas = atomicmass of V-51*x + atomicmass of V-50*(100-x)/100

average atomicmas of v = 50.9415 amu

atomicmass of V-51 = 51 amu

atomicmass of V-50 = 50 amu

50.9415 = (51*x+50*(100-x))/100

percentage of V-51 = 94.15%

percentage of V-50 = 100-94.15 = 5.85%

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