There was only one trial Equivalence number: 24.54 mL Mass of KHP measured: 0.48

Question

There was only one trial Equivalence number: 24.54 mL Mass of KHP measured: 0.489 g NAME: 16. Repeat the titration with a second KHP solution. Analyze the titration results in a manner similar to your first trial and record the equivalence point DATA TABLE Trial Equivalence point (mL) Use the correct significant figures to read the buret DATA ANALYSIS 1. Using the mass of KHP you measured. calculate the moles ofKHP used in each trial. 2. Calculate the molar concentration of the NaoH solution for each trial using the results of your titration experiment. Show all your work. 3. Compare the actual molarity you calculated for your NaOH solution with the goal of 0.10 M by calculating percent emor for both the trials. Givereasons for the error you observe.

Explanation / Answer

Mass of KHP measured: 0.489 g

Molar mass of KHP: 204.22

Number of moles = amount in g / molar mass

= 0.489 g/204.22 g/ mole

= 2.39*10^-3 moles KHP

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.