Select the correct set of products for the following reaction Ba(OH)_2 + HNO_3 (

Question

Select the correct set of products for the following reaction Ba(OH)_2 + HNO_3 (aq) rightarrow BaN_2(s) H_2O (l) Ba(s) H_2(g) NO_2(g) No reaction occurs Select the net ionic equation for the reaction between sodium chloride and mercury(1) nitrate. 2NaCI (aq) + Hg_2(NO_3)2(aq) rightarrow NaNO_3 (aq) + 2 Hg_2 CI_2(s) Na^+(aq) NO_3(aq) rightarrow NaNO_3 (aq) Hg_2^2+(aq) + 2Cl^- (aq) rightarrow Hg_2Cl_2(s) NaCl(aq) rightarrow Na^+(aq) Cl^- (aq) Select the spectator ions for the following reaction. Pb(NO_3)_2(aq) NaCl(aq) rightarrow PbCl_2(s) + NaNO_3(aq) Pb^2+(aq), Cl^- (aq) Na^+ (aq), NO_3^- (aq) Pb^2+ (aq), NO_3^- (aq) Na^+ (aq), Cl^- (aq)

Explanation / Answer

Q4.

This is acid + base reaction = water + salt will be formed

so

Ba(OH)2 + 2HNO3 = Ba(NO3)2 + 2H2O(l)

so... solution is B, since H2O is only a product, the coefficient is not included

Q5.

net ionic equation = includes ONLY ions forming the precipitate so

Hg2Cl2 = solid, so include Hg's and Cl's ions

so

Hg2+2(aq) + 2Cl-(aq) = Hg2Cl2(s)

choose B

Q6

spectator ions are those that remain in solution after precipitate forms

so

in the product side, NaNO3 is aqueous so, Na+ and NO3- are in ions...

since those are also included in the left side, then Na+ and NO3- are jsut spectator ions

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