A student measured the diameter of a sphere and determined the average value. Hi

Question

A student measured the diameter of a sphere and determined the average value. His measurements are 5.17 cm, 5.16 cm, and 5.17 cm. If the diameter is 6.18 cm, what can be said about the student's results? It is accurate and precise. It is accurate but not precise. It is precise but not accurate. It is neither precise nor accurate. What is the de Broglie wavelength of an electron (m = 9.11 times 10^-31 kg) moving at a velocity of 3.0 times 10^7 m/s? de Broglie equation: lambda = h/mv, where Planck's constant, h = 6.626 times 10^-34 Kg middot m^2/s. less than 3.9 times 10-12 m 2.4 times 10-11 m 3.3 times 10-8 m greater than 1.1 times 10^-4 m

Explanation / Answer

4) For the given measurement values found we could say that,

C) It is precise but not accurate

5) de brogliw wavelength (l) would be,

l = h/mv

  = 6.626 x 10^-34/3 x 10^7 x 9.11 x 10^-31

  = 2.4 x 10^-11 m

Answer : B) 2.4 x 10^-11 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.