What is the absorbance of a solution with a 57.34% T? When 5.00 mL of 0.0200 M F

Question

What is the absorbance of a solution with a 57.34% T? When 5.00 mL of 0.0200 M Fe(NO_3)_3 is mixed with 5.00 mL of 0.00200 M NaSCN it is found that at equilibrium FeNCS^2+ is produced with a concentration of 7.00 times 10^-4 M. Calculate the equilibrium concentration of all species present and the equilibrium constant K_c for the reaction below. Fe^3+(aq) + SCN^-(aq) irreversible FeNCS^2+(aq) If 50.0 mL of 0.200 M Fe(NO_3)_3 is mixed with 75.0 mL of 0.300 M NaSCN, calculate the equilibrium concentration of FeNCS^2+. You will need to use the equilibrium constant that you calculated in the last problem.

Explanation / Answer

4) the relation between absorbance (A) and percent transmittance (%T) is as follows:

A = 2-log %T

A=2-log(57.34)

A=2-1.7584

A=0.2416

Hence, Absorbance is 0.2416

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