ning.com/ibiscms/mod/ibis/view.php?id 4345413 Jur o 1/14/2018 12:00 PM @ 9.5/201

Question

ning.com/ibiscms/mod/ibis/view.php?id 4345413 Jur o 1/14/2018 12:00 PM @ 9.5/201/11/2018 10:51 AM Gradeboo Print Caloustor Periodic Table Sapling Learning Low concentrations of met readings: 190.7, 155.9, 147.7, 159.7, 204.7, 145.5, 208.5, 187.1, 120.1, and 190.9. Ten blanks had a mean concentra near the detection limit the dimensionless instrument of 42.9. The slope of the calibration curve is 2.58 x 10M Estimate the signal and limits and the lower lirnit of quantitation for methylmercury Number Signal Detection Limit: 70.50 Number Concentration Detection Limit Number Lower Limit of Quantitation There is additional feedback View this feedback by clicking on the bottom divider bar on the divider bar again to hide the adctional teedback Close OPrevous Grve Up & View Solution #Try Again ONext 8Ed.

Explanation / Answer

The average of the measurements is: 171.08 The standard deviation is: 29.29. We assume the standard deviation of the blanks is the same.

So, the signal at the detection limit is:
yLOD = yblank + 3sblank yLOD = 42.9 + 3(29.29) = 130.77

We can use the slope to convert this to a concentration: LOD = 130.77/(2.58x10^9 M^-1) = 5.068x10-8 M

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.