4) A student was given a mixture containing copper oxide (insoluble) and copper

Question

4) A student was given a mixture containing copper oxide (insoluble) and copper sulfate (soluble) and asked to separate them. Firstly, she stirred the mixture into water, then filtered it. Next she evaporated the filtrate a. What substance was the residue in the filtration? b. Describe what the filtrate was. c. What difference in properties allows substances to be separated by filtration? What substance was collected by evaporation? What difference in properties allowed for this separation? d. e.

Explanation / Answer

a) Copper oxide.

Reason - it is insoluble in water. So it will not pass through the filter.

b) Copper sulphate.

Reason- it is soluble in water. So it will pass through the filter along with water.

c) Solubility of substances

d) Copper sulphate

e) Boiling point of substances.

Explanation- Copper sulphate is soluble in water and has a higher boiling point than water. So when the solution is heated, water will evaporate first (at 100C) leaving behind the copper sulphate crystals.

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