1. A solid mixture consists of 28.9 g of KNO3 (potassium nitrate) and 5.1 g of K
ID: 1076539 • Letter: 1
Question
1. A solid mixture consists of 28.9 g of KNO3 (potassium nitrate) and 5.1 g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. If the solution described in the introduction is cooled to 0 C, what mass of KNO3 should crystallize?
Enter your answer numerically in grams.
2. In the PhET simulation, select the solute in the dropdown menu under the beaker. The ionic formula of the solute will display on the beaker. You can click the box adjacent to Show values to display the concentration of each solution. By setting the Solution Volume slider bar to the minimum and the Solute Amount slider bar to the top, you can maximize the number of saturated solutions you create.
List the following compounds in order of increasing concentration for their saturated solutions.
Rank from lowest to highest. To rank items as equivalent, overlap them.
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nickel(II) chloride
gold(III) chloride
copper(II) sulfate
potassium dichromate
nickel(II) chloride
gold(III) chloride
copper(II) sulfate
potassium dichromate
Explanation / Answer
To answer this question we need to look on a solubility diagram (graph) I find the solubility of kno3 to be approximately 15 grams KNO3 / 100 grams H2O, so the next step is to multiply this value by the ammount of water
there are 130 grams of water
130 * 15 = 1950 , divide this by 100
1950 / 100 = 19.5 grams of KNO3 will remain in the solution
the ammount of kno3 that will crystallize is:
28.9 - 19.5 = 9.4 grams of KNO3 will crystallize
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