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pport Services v Question Completion Status: echnical Info QUESTION 1 0.50000 points Save Answer The Cu2+ ions in this experiment are produced by the reaction of 1.0 g of copper turnings with excess nitric acid. How many moles of Cut are produced? 0.031 mol ° 0.016 mol 64 mol C) 32 mol QUESTION 2 0.50000 points Save Answer Why must nitric acid be used to dissolve metallic copper? Why not use hydrochloric acid? Because chloride will interfere with the reactions later in the experiment. Because the reduction of the nitrate ion is what drives the oxidation of the copper. :Because the Htions are more active in nitric acid than in hydrochloric acid. Because the stock room is out of hydrochloric acid. QUESTION 3 0.50000 pointsSave Answer How many grams of metallic copper are required to react with the number of moles of Cu2t calculated in Problem 1 to form the CuCI? The overal reaction can be taken to be: Cick Save and Submit to save and submit. Click Saue Aff Answers to save al ansmers

Explanation / Answer

For question 1, we need to establish the reaction between copper and nitric acid:

Cu + 4HNO3 -> Cu(NO3)2 + 2 NO2 + 2 H2O

We are given 1 gram of Cu, which we will turn into moles:

1 gram Cu * (1mol / 63.456g) = 0.01576 moles

As we can see by the reaction, only one mole is produced of copper ions, while we will produce on the other hand 2 moles of NO3- ions. So 0.01576 moles of copper ions will be produced.

For number 2:

Nitric acid is the only acid that can react with copper, and this is due to the nitric acid is an oxidizing agent. As the nitrogen ion reduces, copper is oxidized, giving a rection. It is not the typical acid-metal reaction.

For number 3:

Stoichiometry of copper ions and solid copper is 1 on 1, so we need 0.01576 moles of solid copper, which going backwards, gives us 1 gram of solid copper.

For number 4:

Maximum mass of CuCl will be determined as follows:

0.01576 moles of copper ions * (2 moles of CuCl / 1 mol of ions)

Hence, we will be producing a max. of 0.03151 moles of CuCl, which in grams is:

0.03151 mol CuCl * (98.99 grams / mol) = 3.12 grams of CuCl

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