b) Calculate the molarity of the HNO c) Practice: If 25 mL of 0.10 M NaOH neutra

Question

b) Calculate the molarity of the HNO c) Practice: If 25 mL of 0.10 M NaOH neutralize 15 mL of H,SO, what is the molarity of the H,So. d) Practice: If 15 mL of 0.10 M NaOH neutralize 15 ml. of HNO, what is the molarity of the HNO,? e) Practice: If 15 mL of 0.10 M NaOH neutralize 25 mL of HCl, what is the molarity of the HC1? Part 6-COLLIGATIVE PROPERTIES (Practice for homewors) I. Look at the results in the data table below and answer question #2 below: 100 mL of water 100 mL water +0.1 mol Naci 100 ml water +0.1 mol Time required to Boil Time required to Freeze 5 min 120 min 8 min 160 min 140 min 2. Which solution will have the highest boiling point and highest freezing point? Explain why?

Explanation / Answer

Calculate molarity of solutions

c) H2SO4 + 2NaOH --> Na2SO4 + 2H2O

moles NaOH used = 0.1 M x 25 ml = 2.5 mmol

moles H2SO4 present = 2.5/2 = 1.25 mmol

molarity of H2SO4 solution = 1.25 mmol/15 ml = 0.083 M

d) HNO3 + NaOH --> NaNO3 + H2O

moles NaOH used = 0.1 M x 15 ml = 15 mmol

moles HNO3 present = 1.5 mmol

molarity of HNO3 solution = 1.5 mmol/15 ml = 0.1 M

e) HCl + NaOH --> NaCl + H2O

moles NaOH used = 0.1 M x 15 ml = 15 mmol

moles HCl present = 1.5 mmol

molarity of HCl solution = 1.5 mmol/25 ml = 0.06 M

[Formulas used,

molarity = moles/L of solution]

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