For the reaction: 2N205 (g) 4NO2(g) + O2(g) After the reaction had run for a whi

Question

For the reaction: 2N205 (g) 4NO2(g) + O2(g) After the reaction had run for a while, 0.70 M of N205 was consumed. What was the molarity of NO2 and Op made? 1.40 M of NO2 was produced, and 0.70 M of O2 was produced. 0.35 M of NO2 was produced, and 14 M of O2 was produced. 0.70 M of NO2 was produced, and 0.70 M of 02 was produced. 1.4 M of NO2 was produced, and 0.35 M of 02 was produced 2.8 M of NO2 was produced, and 0.35 M of O2 was produced 2.8 M of NO2 was produced, and 0.70 M of 02 was produced 704

Explanation / Answer

according to reaction taking place
2 M of N2O5 give 4 M of NO2
1 M of N2O5 give 4/2 M of NO2
0.70 M of N2O5 give (4/2)*0.70 M of NO2
0.70 M of N2O5 give 1.4 M of NO2

SO, 1.4 M of NO2 was produced

again,
according to reaction taking place
2 M of N2O5 give 1 M of O2
1 M of N2O5 give 1/2 M of O2
0.70 M of N2O5 give (1/2)*0.70 M of O2
0.70 M of N2O5 give 0.35 M of O2

so, 0.35 M of O2 was produced

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