The vapor pressure of liquid propanol, C,H OH, is 100. mm Hg at 326 K H is place
ID: 1082995 • Letter: T
Question
The vapor pressure of liquid propanol, C,H OH, is 100. mm Hg at 326 K H is placed in a closed, evacuated 593 ml. container at a temperature of 326 K. It is found that all of the C,H,OH A sample of C,H-O is in the vapor phase and that the pressure is 59.0 mm Hg. If the volume of the container is reduced to 364 mL at constant temperature, which of the following statements are correct? Choose all that apply Only propanol vapor will be present. No condensation will occur Some of the vapor initially present will condense. The pressure in the container will be 100, min Hg. Liquid propanol will be present.Explanation / Answer
Propanol at 326K and 59.0mmHg pressure is in vapor phase initially. Now calculate the vapor pressure when volume is reduced to 364mL at constant temperature
At constant temperature, as the volume of the gas decreases, the pressure increases, from the equation
P1V1 = P2V2
Given that P1 = 59.0mmHg; V1 = 593mL
V2 = 364mL and P2 = ?
P2 = P1V1/V2 = 59 X 593/364 = 96.11mmHg
The pressure is 96.11mmHg at 326K
Given that the vapor pressure of propanol at 326K is 100mmHg, at this pressure the liquid and vapor are at equilibrium
Now lets compare the calculated pressure 96.11mmHg with the given vapor pressure pressure 100mmHg at 326K
Since the calculated pressure of propanol is 96.11mmHg, which is less than 100mmHg so no condensation will take place and the sample will remain in the vapor phase at 96.11mmHg.
No condensation will occur and only propanol vapor will be present
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