Show calculations and be mindtul of signiticant bgures tor tull credit The follo

Question

Show calculations and be mindtul of signiticant bgures tor tull credit The following data were observed in an equivalent mass of an acid experiment. 1) Fill in the blanks (2 points each). Show all calculations for full credit volume Final volume Net volume NaOH molarity Acid mass 0.1000 M 0.2511g 34 Numerical value: 2) (3 points) How many moles of hydroxide ion were consumed in the titration? 3) (G points) How many moles of hydronium ion were available from the acid? 4) (4 points) What is the equivalent molar mass of the acid?

Explanation / Answer

2)

Volume of NaOH consumed = 33.6ml - 0.2ml = 33.4ml

Moles of hydroxide(OH-) ions = (0.1mol/1000ml) × 33.4ml = 0.00334mol

3)

moles of hydroxide ions consumed = moles of Hydronium ions were available

Therefore,

moles of Hydronium ions(H3O+) available = 0.00334mole

4)

Moles of Hydronium ions = No of Equivalents

Equivalent molar mass = mass /No of Equivalents

Equivalent molar mass = 0.2511g/0.00334Eq = 75.18g/Eq

5)

Tartaric acid

If multiply by Equivalent molar mass by 2 the result is 150.18g/mol which is equal to molar mass of tartaric acid.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.