o 2/14/2018 06:00 PM 90/1002/13/2018 03:21 PM Question 9 of 10 Sapling Learning

Question

o 2/14/2018 06:00 PM 90/1002/13/2018 03:21 PM Question 9 of 10 Sapling Learning Consider this reaction data If you were going to graphically determine the activation energy this reaction, what points would you plot? A products Number T(K) (8-1) 225 0.393 725 0.786 To avoid rounding errors,use at least three significant figures in all values point 1 : Number- Number point 2: 1 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the activation energy of this reaction? Number J/mol -O Previous Give Up & View Solution Check Answer 0 Next Exit- Hint

Explanation / Answer

here graph is drawn between ln K   and 1/T

lnK = y -axis

1/T = x - axis

point 1:   x = 4.44 x 10^-3   ,   y = -0.934

point 2 : x = 1.379 x 10^-3   , y = -0.241

rise =   y2-y1   = 0.693

run = x2 - x1   = - 3.06 x 10^-3

slope = rise / run = - 0.693 / 3.06 x 10^-3 = - 226

-Ea / R = slop

Ea = 226 x 8.314 = 1879.8 J / mol = actiavation energy

actiavation energy = 1.88 x 10^3 J/mol

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