D TRACS: DH Chapter AccessCergage 13377903078narer hons he plye solven graph Dep
ID: 1085740 • Letter: D
Question
D TRACS: DH Chapter AccessCergage 13377903078narer hons he plye solven graph Depequal to one anotther Apps gLTRACS Catsweb :1 Bobcat Mal D Culurai Anthropolog..G,Heinle Learning Cert. D Cengage tinse MINDTAP Lab 2- Finding the Molar Mass of an Unknown by Measuring the Freezing Point Dep.. e Due Today at 10 PM CST ng time (min) ntermédiate value inal value Time TempTime Temp Cc) rc) intermediaFinal ? 0.1 Pure Solvent Freezing Data 0.5 2.5 5.5 0.1 2.5 ". 1.0 0.1 1.5 1.3 6.5 1.0 7.0 0.1 7.5 V-0.0072727z-0.056364 0.0 Time (min) Plot showing the freezing data of the pure solvent SCORE: 0% SAVED:V () Zoom Dark SUBMIT ACTIVITY 0 aps lock ontrol optioncommand commandoptionExplanation / Answer
Freezing point depression can be obtained by the intersection of two curves.
y= -0.89762x+2.7833= 0.0072727x-0.056364
solving for x, x*(0.0072727+0.89762)= 2.7833+0.056364
x= 3.138122 , this is the time at which freezing point depression occurs
the freezing point is y=-0.89762*3.138122+2.7833= -0.03354 deg.c
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