Spec Exercise (5 pts) Infrared spectroscopy is to differentiate between two or m
ID: 1087623 • Letter: S
Question
Spec Exercise (5 pts) Infrared spectroscopy is to differentiate between two or more compounds based on the p not typically used alone to solve the structure of a compound, but it does permit one resence or absence of certain peaks. For example, let's say that in running the TLC experiment that you find more that than one spot occurs in a standard, but the unexpected spot the second contaminated the does not seem to correspond to any other standard by TLC. Assuming that spot has to be one of the other compounds (unless aliens have invisibly e standards) then IR might help you sort out which standard is the contaminant. You unexpected research the IR spectra of the three analgesic components and find the following spectra. Acetaminophen Aspirin Caffeine Exercise: Make a short table with three columns for the compounds (draw each molecule) and list under each one the presence and absence of two functional groups (an In/Out Table) and the approximate location of their absort them.Explanation / Answer
Acetaminophen IR
Carbonyl group -C=O 1685 cm-1
Broad band at 3500 cm-1 is due to hydroxy group
Band at 3050 cm-1 is due to aromatic CH stretching
Band at 2840 - 2950 cm-1 is due to aliphatic CH stretching
No band around 2100 cm-1 show the absences of nitrile and alkyne group.
Asprin IR
Band at around 1750 and 1650 cm-1 is due to carbonyl group
Broad band at around 3200 cm-1 is due to hydroxy group of carboxylic acid
Band at around 3025 cm-1 is due to aromatic CH stretching
Band between 2840 - 2950 is due aliphatic CH streaching
No band around 2100 cm-1 show the absence of nitrile ground and alkyne group.
Caffeine
Band between 1680 - 1750 is due carbonyl group, band between 2850 - 2945 cm-1 is due to aliphatic CH streaching,
Weak band around 3025 cm-1 is due to aromatic CH stretching
No broad band around 3300 - 3500 cm-1 show absence of hydroxy group,
No band around 2100 cm-1 show absence alkyne group
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