129 Rates of Chemical Reactions, L. The lodination of Acesone Name Section Advan

Question

129 Rates of Chemical Reactions, L. The lodination of Acesone Name Section Advance Study Assignment: The lodination of Acetone In a reaction involving the iodination of acetone, the following volumes were used to make up tion misture: l. 10 ml. 4.0 M acetone+10 mL. 1.0 M HCI+10 mL.0.0050 M1,+30 mL. H.O a How many moles of acetone were in the reaction mixture? Recall that, for a component A, no moles A M,xV, where M, is the molarity of A and Vthe volume in liners of the solution of A that was used moles aceone b. What was the molarity of acetone in the reaction mixture? The volume of the mixture was 50 ml. 0050 liter, and the number of moles of acetone was found in Part a. Again no. moles A Vof soln. in liters M acetone c. How could you double the molarity of the acetone in the seaction misture, keeping the soal volume at 50 mL and keeping the same concentrations of H' ion and I, as in the original misture? 2 Using the reaction misture in Problemoud thi 0cs for the color of the to disappear a. What was the rate of the reaction? Hint: First find the initial concentration of I, in the reaction mix- ture, (ay Then use Equation 5 h Given the rate from Part a, and the initial concentrations of acetone, H ion, and I, in the reactioe mix- ture, write Equation 3 as it would apply to the mixture c. What are the unknowns that remain in the equation in Part b? (continued on following page)

Explanation / Answer

1 a. The initial no. of millimoles acetone = 10 mL * 4 mmol/mL = 40 mmol

Therefore, the no. of moles of acetone in the reaction mixture = 40*10-3 mol = 4*10-2 mol

b. The total volume = (10+10+10+20) mL = 50 mL = 50*10-3 L = 5*10-2 L

Therefore, the concentration of acetone in the reaction mixture = no. of mol of acetone/total volume

= 4*10-2 mol/5*10-2 L

= 0.8 M

c. By doubling the volume of 4 M acetone solution (i.e. 20 mL) and by halving the volume of water (i.e. 10 mL)

Now, the concentration of acetone = 20*4/50 = 1.6 M

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