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m 531 Constar1 Perk de Table Solutions of sulfuric acid and lead(W) acetate reac

ID: 1089056 • Letter: M

Question

m 531 Constar1 Perk de Table Solutions of sulfuric acid and lead(W) acetate react to form sold eadill) sulflate and a solution of acetic acid. 5.70 g of sulfuric acid and 5.70 g of leadll) acetate are mixed You may want to reference (Pages 106 110) Section 3.7 while completing this problem Correct TO solve forthe amount ofload) sulfato leftover aferthe reaction, set up a dimensional aaysis. Since lead(U) acetato sihe determine from the balanced chemical equatsion that 1 mol of leadklil) acetate reacts for each 1 mol of leadkll) sulfate produced H,so, + Pb(CH3COO): Pbso, + 2 CH3COOH wo can make the assrption tat for every mole of lead) acotato onsumed, one mole ofloadm sultne was produced. Keep eadl) suifabe is 303.3 g/mol. Mass of Ptso, Produced-5.70 8 PbtH,COO) Feedback: Your answer 5.30 g was elther rounded differently or used a difforent number of significant figures -Part D Calculate the number of grams of acetic acid present in the mixture after the reaction is complete Express your answer using three significant figures. Provide Feedback 2 3 4 5 6 7 8 0

Explanation / Answer

from equation,

1 mol H2SO4 = 1 mol lead acetate = 2 mol acetic acid

limiting reactant = lead acetate

No of mol of lead acetate reacted = 5.7/325.3 = 0.0175 mol

No of mol of acetic acid formed = 0.0175*2 = 0.035 mol

amount of acetic acid formed = 0.035*60 = 2.10 g