2 A student performed a food calorimetry experiment on a cracker with a mass of

Question

2 A student performed a food calorimetry experiment on a cracker with a mass of 16.23 g. At the end of the experiment, the ash remaining had a mass of 1.39 g a If the temperature of 99.68 g water increased from 23.5°C to 72.9°C during the experiment, what is the energy content of the cracker in calories per gram? Show your work to justify your answer b The-Calories" reported on nutrition labels are actually kilocalories (1 kilocalorie = 1,000 calories). What is the energy content of this student's cracker in Calories per gram? Show your work to justify your answer Lab 3 Calorimetry and Specific Heat

Explanation / Answer

mass of food reacted = 16.23-1.39 = 14.84 g

heat released(q) = m*s*DT

m = mass of water = 99.68 g

s = specificheat = 4.184 j/g.c

DT = (72.9-23.5)

q = 99.68*4.184*(72.9-23.5)

= 20.6 kj

heat content = -20.6/14.84 = -1.4 kj/g

energy content = -1.4/4.184

               = -0.335 kcal/g

               = -335 cal/g

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