2. (total 50 points) Consider the following reaction representing the combustion

Question

2. (total 50 points) Consider the following reaction representing the combustion of propane: C3Ha + O2 CO2 + H2O (a) (10 points) Balance the equation (b) (10 points) How many moles of oxygen are required to burn I mol of propane? (c) (10 points) How many grams of oxygen are required to burn 100 g of propane? (d) (20 points) At standard temperature and pressure (STP, OC, 1 atm), what volume of oxygen (m2) would be required to burn 100 g of propane? If air is 21 percent oxygen, what volume of air at STP would be required? (gas constant, R-82.05x 10+ atm m/mol K)

Explanation / Answer

a)

balanced equation :

C3H8   + 5 O2    ----------------> 3 CO2   + 4 H2O

b)

from the balanced equation :

1 mol propane needs ------------> 5 mol O2

moles of O2 required = 5 mol

c)

C3H8   + 5 O2    ----------------> 3 CO2   + 4 H2O

44.1 g      160 g

44.1 g C3H8   --------------> 160 g O2

100 g C3H8    ---------------> ??

mass of O2 needed = 100 x 160 / 44.1

mass of O2 needed = 363 g

d)

moles of O2 = 22.68 mol

P V = n RT

1 x V = 22.68 x 0.0821 x 273

V = 508 L

volume of O2 = 508 L

volume of air = 106.7 L

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