Any help is appreciated! Chm 130L Quiz Week 6: Specific Heat Name DateScore10 Th

Question

Any help is appreciated!

Chm 130L Quiz Week 6: Specific Heat Name DateScore10 This is a Take-Home Quiz that is due at the beginning of the next class 1) A 32.595 g sample of an unknown metal was heated to 98.5 C in a hot water bath. The metal was then placed in a calcrimeter containing 65.0 mL of water (densitywaer 1.00 gimL) at a temperature of 26.4C. The final temperature of the water and metal sample was recorded as 30.2 Answer the following questions (2 pts each) given the following: ATTt Specific Heat (s)- hatT (mass(AT) mAT a) Dedermine the temperature change for the warer contained in the calorimeter. (2 pts) b) Calculate the heat (q) absorbed by the water in the calorimeter (provide answer with 3 significant figures) NOTE: Specfic Heat of water is 4.184 g'C (3 pts) c) Determine the temperature charge for the unknawn metal sample (2 pts) d) Calculate the specfic heat of the unknown metal sample. Assume the heat given away by the metal equals the heat absorbed by the water in the calorimeter (i.e., GwQestar). (provide answer with 3 significant figures) (3 pts)

Explanation / Answer

A.

Temperature change of water in colorimeter = 30.2 - 26.4 = 3.8 degree C

B.

Heat absorbed by water = 65.0 * 4.184 * 3.8 = 1033.4 J

C.

Temperature change of metal = 30.2 - 98.5 = 63.3 degree C

D.

1033.4 = 32.595 * specific heat * 63.3

Specific heat of metal = 0.499 J / g-mol

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