BA 15.3 Composition and its Effect Page 4 of Concentration from Densi Part B: 1

Question

BA 15.3 Composition and its Effect Page 4 of Concentration from Densi Part B: 1 Mass of Density, Mass of Mass of Unknown Volume, ml Code Container, g Liquid, g ,0 Part C: Make Up Solution Mass of sucrose, Volume of final solution, ml ( oro entration, 100.0 ml Part C: Determine density Volume, m.Mass of Empty Container, g Mass of Container + Mass of Liqud,Density,gml. RESULTS Part B: Use your graph to estimate the concentration of your unknown solution s) Unknown Code Unknown Code_ Concentration Part C: Use your graph to estimate the density of the solution that you prepared Make up Solution Concentration Estimated Density How does the estimate compare with your actual density measurement? Excellent (within 0.01 g/mL) Fair (within 0.04-0.08 g/mL) Good (within 0.02-0.04 g/mL) Poor (more than 0.08 gmL) 40

Explanation / Answer

Part B: Estimating Concentration from Density

The last column of the table containing Class Average Density (gm/l) cannot be determined unless we know the number of students in the class.

Part C: Make up solution

Given mass of sucrose (C12H22O11) = 7 g

Now Concentration in %w/v means amount of solute in grams dissolved in 100 ml of solution,

Therefore conentration is 7% w/v of sucrose in 100 ml of final solution.

Extra information

Molar mass of sucrose = 12x12 + 1x22 + 16x11 = 342

Moles of sucrose (n) = given mass/molar mass = 7/342 = 0.0204

Given volume of final solution = 100ml = 0.1L

Concentration = moles of sucrose/Volume of solution in litres

Concentration = 0.0204/0.1 = 0.204 M

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