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calculate molarity of HCI labs.laten Dashboard Late Nite Labs File Edit- Insert-

ID: 1090083 • Letter: C

Question

calculate molarity of HCI labs.laten Dashboard Late Nite Labs File Edit- Insert- View. Format- Table- Tools Formats- Paragraph Verdana 11pt 1. For your coarse titration record the following results. volume of NaOH solution in the burette at the start 50.00 mL (mL) volume of NaOH solution in the burette at the end 42.00 mL (mL) volume of NaOH solution dispensed (mL) volume of HCI solution in the flask (mL) 10.03 mL 18.09 mL Data Analysis 9 2. Calculate the molarity of the HCl concentration using your coarse titration results. SUBMIT FOR GRADING SAVE AND FINISH LATER Discard ch

Explanation / Answer

Ans. Note: To calculate molarity of HCl, the molarity of standard NaOH must be known. # In this question, the molarity of NaOH is not provided. So, the solution is provided assuming molarity of NaOH be M2.

Volume of NaOH consumed = 10.03 mL

Volume of HCl consumed = 18.09 mL

# Balanced reaction:             NaOH(aq) + HCl(aq) ------> NaCl(aq) + H2O(aq)

1 mol NaOH neutralizes 1 mol HCl.

# At the equivalence point, moles of H+ produced by acid must be equal to the moles of OH- produced by the base.

That is-           x(M1V1), acid = y(M2V2), base

            Where, x = moles of H+ produced per mol acid

                        y = moles of OH- produced per mol base.

Since the acid and base are monoprotic and monobasic, respectively, x=y=1.

            Or, (M1V1), HCl = (M2V2), NaOH

            Or, M1 x 18.09 mL = M2 x 10.03 mL

            Or, M1 = (M2 x 10.03 mL) / 18.09 mL

            Hence, M1 = 0.22445M2

Therefore, molarity of HCl, M1 = 0.22445M2

            Where, M2 = Molarity of NaOH

Note: Put the value of M2 provided to you in above expression to get the molarity of HCl.

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