Question 28 of 28 The equilibrium constant, K, of a certain first order reaction
ID: 1090241 • Letter: Q
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Question 28 of 28 The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T. If you were going to graphically determine the enthalpy, AH°, for this reaction, what points would you plot? The data is shown in this table. Number Number k point 1: T (K) 225 3.18 To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values. 875 7.14 Number Number point 2: Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number What is the standard enthalpy of this reaction? Number AH° = J/mol O Previous @ Give Up & View Solution Check Answer o Next Exit I ? HintExplanation / Answer
here graph is drawn between ln K and 1/T
lnK = y -axis
1/T = x - axis
point 1: x = 4.44 x 10^-3 , y = 1.157
point 2 : x = 1.14x 10^-3 , y = 1.966
rise = y2-y1 = 0.809
run = x2 - x1 = - 3.30 x 10^-3
slope = rise / run = - 0.809 / 3.30 x 10^-3 = - 245
-deltaH / R = slope
delta H = 266.7 x 8.314 = 2038 J / mol
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