Find x such that P ( X x ) = 0.9382. (Round \" z \" value to 2 decimal places, a

ID: 1104676 • Letter: F

Question

Find x such that P(X x) = 0.9382. (Round "z" value to 2 decimal places, and final answer to nearest whole number.)

Find x such that P(X > x) = 0.025. (Round "z" value to 2 decimal places, and final answer to nearest whole number.)

Find x such that P(2,300 X x) = 0.1217. (Round "z" value to 2 decimal places, and final answer to nearest whole number.)

Find x such that P(X x) = 0.484. (Round "z" value to 2 decimal places, and final answer to nearest whole number.)

Let X be normally distributed with mean = 2,300 and standard deviation = 1,000. Use Table 1.

a) Prob(Z<z) = 0.9832 impliess z = 1.54. Using z= (x-u)/sd

x=1.54*sd+u

x= 1.54*1000+2300 , x= 3840.

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