Q1. Two house designs have been developed one with high levels of insulation, on
ID: 111374 • Letter: Q
Question
Q1. Two house designs have been developed one with high levels of insulation, one with standard levels (see table).
House Areas:
Walls: 133m^2, Floor: 200m^2,Roof: 200m^2,Windows: 33m^2,
House 1 R values (m^2 K/W)
Walls: 2.0, Floor: 1.3, Roof: 3.3, Windows: 0.26
House 2 R values (m^2 K/W)
Walls: 3, Floor: 2, Roof: 4, Windows: 0.3
Determine the total heat loss from these two house designs if the internal temperature is 18 o C and external temperature is 6 o C. What amount of electricity is required to heat this house for the following 3 types of heating system:
- Electric heater
- Air source heat pump (assume 50% of maximum theoretical efficiency e.g. Carnot)
- Ground source heat pump (assume ground temp of 12 o C and 50% of maximum theoretical efficiency e.g. Carnot)
Comment on the results.
Explanation / Answer
Heat loss of House 1
From walls = 133*2*(18-6) = 3192 watts
From floors= 200*1.3*(18-6) = 3120 watts
From roof =. 200*3.3*(18-6) = 7920 watts
From windows = 33*0.26*(18-6) = 102.96watts
Total heat loss= 14334.96 watts = 14.334kilowatth
Heat loss of house 2
From walls= 133*3*(18-6) = 4788 watts
From floors = 200*2*(18-6) = 4800 watts
From roof = 200*4*(18-6) = 9600 watts
From windows = 33*0.3*(18-6) = 118.8 watts
Total heat loss = 19,306.8 watts = 19.306 kilowatts
A higher amount of electricity is required to heat the second house compared to the first house because of its high level insulation for electric heater, air source heat pump and also ground source heat pump.
Note: you have mentioned about a table, but I couldnt find
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