The analysis of a coal is reported as follows (wt. %) Moisture 2.2 Volatile Matt
ID: 111904 • Letter: T
Question
The analysis of a coal is reported as follows (wt. %)
Moisture 2.2
Volatile Matter (db) 28.1
Fixed Carbon (db) 58.5
Ash (db) 13.4
Carbon 74.9
Hydrogen 4.7
Sulfur 0.76
Oxygen 4.97
Nitrogen 1.27
HHV (db) 13,260 BTU/lb
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(a) Calculate “as determined” proximate and ultimate analyses
(b) Determine the ASTM rank of the coal
(c) Calculate the lower heating value of the coal
(d) Calculate the lb of sulfur dioxide emitted per million BTUs as fired
Explanation / Answer
a) Proximate analysis includes the moisture(2.2 wt%), ash content (13.4 db), volatile matter (28.1 db) and fixed carbon (58.5 db).
The ultimate analysis includes carbon (74.9 wt%), hydrogen (4.7 wt %), nitrogen (1.27 wt %), sulphur (0.76%) and oxygen (4.97 wt %).
b) According to the high heating value, the ASTM rank of this coal is high volatile bituminous coal.
c) LHV= HHV - 0.212*H - 0.0245*M - 0.008*Y
= 13258.909 BTU/lb, where H is hydrogen, M is moisture and Y is oxygen
d) Each pound of coal contains 0.76 pound of sulphur. If all the sulphur forms sulphur dioxide then the mass of sulphur dioxide will be 0.76* (Mass of sulphur dioxide /sulphur) = 0.76 * 64/32 = 1.52lb. Since each pound has 13,260 BTU = 0.013 MMBTU, sulphur dioxide production per million BTU is 1.52/0.013 = 344.036lb
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