Ice thickness: The conductive heat flow or heat flux F (in W/m2) up through an i
ID: 112375 • Letter: I
Question
Ice thickness: The conductive heat flow or heat flux F (in W/m2) up through an ice layer is given by where (= 2 W/m/K) is the thermal conductivity of ice, is the temperature difference in K from the bottom to the top of the ice layer, and z is the thickness of the layer in meters. We know that the current geothermal heat flux F—-the heat flow up through the surface of the Earth—-is about 0.06 W/m2. Assume that F had this same value at 0.6 Ga. Assume also that the top of the surface ice layer was at temperature Ts, and that the water below the ice had a temperature of 271 K (-2°C). Compute the thickness of the ice at 0.6 Ga. You can use the ice thickness tool to compute z for given values of and F. 7 points
Explanation / Answer
Ice as we all know that it is the solid phase of water in which we can check the thermodynamics property for a liquid.
The density of ice is Very low as compared to the water. It is because to the fact that during the solidification of water in a low temperatures the air get trapped inside the watet molecules and due to which makes it more porous. Thus porosity creare it to less denser as compared to water.
During this process the thermodynamics state of property for solid phase also get reduced. This reduction when procees in between a thermal state of process it decreases the thickness of it resulting that we will get less thicker ice cube. And the thickness will be. (6*2)/4.82=.2854 is the thickness of the ice.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.