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The Table to the left contains the data that you will need to perform the follow

ID: 113047 • Letter: T

Question

The Table to the left contains the data that you will need to perform the following assignment. You are a teacher doing a lesson on astronomy in 4th grade. You want to give your students an appreciation for the size of the solar system. The principal gives you permission to use the entire length of the central hallway in your school, which is 60 meters long. That's the maximum distance that you have to work with. So, in order to scale the the distance between each planet and the sun, and also to scale the diameters of the planets so that the whole thing is the same proportion as the real solar system, you will have to determine a conversion factor that will make Neptune, the most distance planet, no more that 60 meters from the Sun. (Keep in mind that the units in the Table are in kilometers, and the hallway is in meters.) In other words, this assignment is to create a model of the solar system that has the same proportions as the real solar system, but will fit in a 60 meter-long hallway. You only need the data in Column B and C. The rest in irrelevant for this assignment. This is a scaling problem and this one reason why scaling is important. Once you have determined the conversion factor that will accurately scale the real solar system distances to your hallway, calculate the scaled distance and the scaled diameter so that your solar system fits in the hallway. In column F, suggest an item or object that may work as a substitute for the Sun and planets for your model solar system. This assignment is worth 20 points.

SHOW ALL WORK, especially how you derive you conversion factor.

NOTE: Don't forget that whatever conversion factor you compute has to be applied not only to the distance but to the diameters too, o even the sun is going to be really small on this scale and Mercury is so tiny that it'll be hard finding an object that you would use to represent it

Name of Planet Average Distance from Sun Diameter Scaled Distance Scaled Diameter Object or Item Sun 0 1,392,000km Mercury 57,900,000 km (36,000,000 miles) 4878 km (3,031 miles) Venus 108,160,000 km (67,000,000 miles) 12,104 km (7,926 miles) Earth 149,600,000 km (92,960,000 miles) 12,756 km (7,926 miles) Mars 227,936,640 km (141,700,000 miles) 6,794 km (4,22 miles) Jupiter 778,369,000 km (483,500,000 miles) 142,984 km (88,846 miles) Saturn 1,427,034,000 km (888,750,000 miles) 120,536 km (74,900 miles) Uranus 2,870,658,186 km (1,783,744,300 miles) 51,118 km (31,763 miles) Neptune 4,496,976,000 km (2,797,770,000 miles) 49,532 km (30,779 miles)

Explanation / Answer

Given, total solar system(Ss) length as 4496976000000 m

And total hall way (Hw) distance as 60m

So to find the scale for doing this assignment we need the ratio Hw/ss

Ie, 60/ 4496976000000

Which is = 1/74949600000 ie 1:74949600000

To find fistance for each planet we can use the equation

1/74949600000 = Hw/Ss

by substituting different values for Ss as distance of each plane, we can find its hall distance

This equation can also be used to find diameter in hall for each planet sun substituting each planet diameter in the place of Ss. Hw will be the diam iin Hall for each planet.

So from calculations answer is:

Name of planet SDist.(m) SDia.(m)

Sun. 0 0.01857

Mercury 0.7725 0.000065

Venus 1.44 0.00016

Earth 1.99 0.00017

Mars 3.04 0.00009

Jupiter 10.38 0.0019

Saturn 19.03 0.0016

Uranus 36.3 0.00068

Neptune 60. 0.00066

Due to time limit can't say objects right now.

Thank you for using Chegg. Review on my answer

Thank you :)

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