4. Consider two parcels of air, one in Honolulu, HI and the other in Anchorage,

Question

4. Consider two parcels of air, one in Honolulu, HI and the other in Anchorage, AK each containing 1 kg of dry air plus some water vapor. Assume that they are both at a pressure of about 1000 mb ·The parcel in Honolulu has a relative humidity of 50% and a temperature of 800F. At that temperature, the parcel of air is capable of "holding" at most about 45 grams of water vapor. ·The parcel in Anchorage has a relative humidity of 78% and a temperature of 60 At that temperature, this parcel of air is capable of "holding" at most about 24 grams of water vapor. a. Which parcel has the most water vapor in it? Show your solution. b. What would happen to the amount of water vapor in Honolulu parcel if it were cooled to the same temperature as the air in Anchorage? c. What would its relative humidity be then?

Explanation / Answer

Answer:1

Relative humidity is the presence of moisture content in air parcel with respect to its saturation pont.

Therefore, we can see in Honolulu case, holding capacity of water vapour is more than anchorage.

Answer:2

If it were cooled at 60F then amount of water vapour increases.

Answer:3

The relative humidity would be become low.

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