Engineering Economics A company uses a variabic speed honing machine to increase

Question

Engineering Economics

A company uses a variabic speed honing machine to increase the smoothness of the inside walls ot hydraulic jacks The hone uses acd-dipped nushes" to perfcrm this operation. Increasing tne speed of the machine results in taster operation, but reduces h usn te A single brush costs $ DD and can be et shed several h het re its usetul ite is over he number on ehitis n s depends on he non ng speed tach retu tis ng cos 40 ssume a returbished brush can smooth the same amount as a new brush, and that when purchased a new brush is ready to use. The operating cost for the hone and operator is SG0 00hr. Below is the data for operating the hone at 3 ditferent speeds. The time required for changing brushes is incorporated into the honing rates below. Which honing speed is the most economical? HINT: find the cost per jack, not per hone or per cyclal of jacks polished until # of times refurbishing is possible Honing Speed Hone Rate the brush need:s refurbishing (rpm) 180 240 (acks/hr) 12 The cosl ack for the honing speed of 180 Ipi is 3 14.55 per jack (Round to the nearest cent.) The cost per jack for the honing speed of 240rpm is per jack. Round to the nearest cent.)

Explanation / Answer

Honing speed of 180rpm is most economical,i.e., $14.55 per jack

Workings:

Honing speed(rpm)

Honing speed(rpm)

No. Of jacks cleaned using 1brush Total cost of brush(purchase+ refurbishing)(in $) No. Of hours worked with 1 brush Operation cost (in$) Total cost (in $) Cost per jack(approx.)(in $) 180 11×(4+1)=55 90+(40×4)=250 55/6 (55/6)×60=550 250+550=800 800/55=14.55 240 7×(2+1)=21 90+(40×2)=170 21/7 (21/7)×60=180 170+180=350 350/21=16.66 300 5×(1+1)=10 90+(40×1)=130 10/12 (10/12)×60=50 130+50=180 180/10=18

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