Ben swims 50,000 yards per week in his practices. Given this amount of training,

ID: 1142505 • Letter: B

Question

Ben swims 50,000 yards per week in his practices. Given this amount of training, he will swim the 100-yard butterfly in 49.8 seconds and place 9th in a big upcoming meet Ben's coach calculates that if Ben increases his practice to 60,000 yards pujweek, his time will decrease to 44.6 seconds and he will place 7th in the meet. If Ben practices 70,000 yards per week, his time will be 43.2 seconds and he will win the meet. In terms of Ben's time in the big meet, what is his marginal productivity of the number of yards he practices? The marginal product of increasing practice yards from 50.000 to 60,000 is second(s) (enter a numeric response using a real number rounded to ane decimal place)

Explanation / Answer

Marginal productivity is the change in time for a change in number of yards

MP = (Change in Time)/(Change in no of yards)

Yards

Time

Marginal Productivity for a yard

Marginal Productivity for every 10000 yard

50000

49.8

60000

44.6

-0.00052

-5.2

70000

43.2

-0.00014

-1.4

Here the productivity is measured in reduction in time consumed; we can consider the absolute value to interpret marginal productivity.
So, the MP of increasing practice yards from 50000 to 60000 is 5.2 seconds