Almost the same as Archer problem 3.1: In class, for the Bare Rock model, we eff

Question

Almost the same as Archer problem 3.1: In class, for the Bare Rock model, we effectively assumed that the entire surface of Earth is at a single temperature, as would be the case if heat were conducted with very high efficiency from Equator to Pole, zeroing out any temperature differences. We could make another extreme assumption that there is no heat transport at all. This is the situation for the moon, which has no atmosphere or ocean to conduct heat poleward. In the original Bare Rock model, the balance between “energy in” and “energy out” holds for the average over the entire surface of the planet. In this alternate model, in contrast, the balance between “energy in” and “energy out” must hold at every square meter of the surface.

So let's consider a moon-like Bare Rock model, but with parameters otherwise similar to the Earth, with an albedo of 0.33, and a solar constant of S0 = 1366 W m-2. What is the equilibrium temperature on the equator, at local noon, when the sun is directly over head? What is the equilibrium temperature on the dark side, when there is no sunlight at all? What is the equilibrium temperature when the sun's zenith angle* is 60°?

Explanation / Answer

ANSWER -

Moon has equilibrium temperature during day timme is 373 kelvin in day time when sun position is directly over head.

The equilibrium temperature of moon on the dark side is 100k.

At Zenith angle it is 271k.

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