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Estimate the minimum size septic tank needed for country hotel/restaurant comple

ID: 115265 • Letter: E

Question

Estimate the minimum size septic tank needed for country hotel/restaurant complex that has an average of 50 hotel guests per day and 100 restaurant customers per day. The restaurant is a conventional restaurant and the hotel/restaurant complex has 10 employees. (See data in Table 2)

Chrome File Edit View History Bookmarks People Window Help O 1) 60% D Mon 1158 AM a = • O BS Homework - 17 FALL AGSM 3 xY AGSM 337 Max C & Secure I https://tamu.blackboard.com/ bbcswebdavpid-3765599-dt-contentrid-26592282-1/courses/AGSM.337.500.173 1/Hw6_17C.pdf O AGSM 337 Marlin Pictures 22 7B7E7 1A4-12 3AB-BEDD6. Assembly hall 2-4 Hospitalmedical Bed 125-240 Employee 5-15 Hospitalmental Bed 75-140 Employee 5-15 Prison Inmate 80-150 20 Employee 5-15 Rest home Resident 50-120 Employee 5-15 School, day-only: with cafeteria, gym, showers Student 15-30 With cafeteria only Student 10-20 Without cafeteria, gym, showers Student 5-17 School, boarding Student 50-100 75 Adapted in part from Tehobanoglous, G. and E.L. Burton (1991) Wastewater Engineering, TreatmentDisposalReuse. Ed, McGraw-Hill, New York Table 2. eal wastewater Flow Rates from Commercial Sources Flow (gal/unit/day) Type of Establishment Uni Range ical Airport Passenger Automobile service station Vehicle served 8-15 12 Employee 9-15 13 Customer Employee 10-16 Department store Toilet room 400-600 500 Employee 8-15 Hotel Guest 40-60 Employee 8-13 10 Laundry (self-service) Machine 450-650 550 Wash 45-55 50 Public lavatory User 3-6 Restaurant 2-4 Conventional Customer 8-10 Short order Customer 3-8 Bar/cocktail lounge Customer 2-4 Theater Seat 2-4 OO D H O'1 o El DeP® 1 1 0 0 8 0 93 w P9 U

Explanation / Answer

Typical waste water produced from guests with a frequency of 50 guests in hotel per day=50*50=2500gal/day

Typical waste water produced from restaurant customers with a frequency of 100 restaurant customers=9*100=900gal/day

Typical waste water produced from restaurant employee=10*10=100gal/day

Therefore cumulative waste water produced per day by guests, restaurant customers and restaurant employee= 2500+900+100=3500 gal

Now, 1 cubic feet of can hold 7.481 gallons

Therefore for holding 3500 gal/day, septic tank should be (3500/7.481) ft3= 467.85ft3

Therefore the minimum size of septic tank should be 467.85ft3

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