Section 3: lonic Bonds Example Sodium (Na) has l l protons and 1 l electrons (at

Question

Section 3: lonic Bonds Example Sodium (Na) has l l protons and 1 l electrons (atomic-). Chlorine (CI) has 17 protons and 17 electrons (atomic #-17), Because of this, Na has a single electron in its 3 energy level and CI has seven. To bond ionically: Cl takes this single electron from Na, completes its 3d energy level, and stabilizes both atoms. As a result, Na has fewer electrons than protons (now, 10 electrons) and CI has more electrons than protons (now, 18 electrons). Therefore, Na has a positive charge (cation) and CI has a negative charge (anion). Cl Na 11 protons, Il electrons 17 protons, 17 clectrons 17 Cl 990 35.453 BondingO Ch 17 protons 18 clectrons Na' I1 protons, 10 electrons the periodic table of elements. Question 1:Look up Sodium (Na) and Fluorine (F) on How many protons does an atom of Na have? How many electrons does an atom of Na have? How many electrons are in the 3"d energy level of Na? How many electrons are in the 2d energy level of F? After bonding, will Na be positively charged (cation) or negatively charged (anion)?

Explanation / Answer

1. There are 11 protons in an atom of Na.

2. There are 11 electrons in an atom of Na.

3. There is 1 electron in the third energy level of Na.

4. There are 7 electrons in the second energy level of F.

5. Na will be positively charged (cation) after bonding.

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