You measure the water potential of the cell and find it to be -3.6 kPa. The pres
ID: 116218 • Letter: Y
Question
You measure the water potential of the cell and find it to be -3.6 kPa. The pressure potential of the same cell is 0.46 kPa. If the cell were placed in a beaker with a solute potential of -2.4 kPa, would the pressure potential of the cell increase or decrease? Why?
A. Decrease. Water would move from the cell into the beaker, thus decreasing the water in the cell and increasing the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential (-3.6 k Pa) to low water potential (-2.4 kPa).
B. Increase. Water would move from the beaker into the cell, thus increasing the water in the cell and the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential to low water potential.
C. Increase. Water would move from the beaker into the cell, thus increasing the water in the cell and the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential (-3.6 k Pa) to low water potential (-2.4 kPa).
D. I do not have enough information to answer this question. I need to know the solute potential of the cell and the solution in the beaker and the pressure potential in the beaker.
A. Decrease. Water would move from the cell into the beaker, thus decreasing the water in the cell and increasing the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential (-3.6 k Pa) to low water potential (-2.4 kPa).
B. Increase. Water would move from the beaker into the cell, thus increasing the water in the cell and the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential to low water potential.
C. Increase. Water would move from the beaker into the cell, thus increasing the water in the cell and the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential (-3.6 k Pa) to low water potential (-2.4 kPa).
D. I do not have enough information to answer this question. I need to know the solute potential of the cell and the solution in the beaker and the pressure potential in the beaker.
Explanation / Answer
answer) option B. Increase. Water would move from the beaker into the cell, thus increasing the water in the cell and the pressure potential. The water potential of the cell is -3.6 kPa. Because the pressure potential of the beaker is zero, the water potential in the beaker is -2.4 kPa. Water moves from a high water potential to low water potential.
because Waterpotential in the beaker= solute potential +pressure potential of the beaker.
= - 2.4 kpa + 0
=-2.4 kPa.
Water moves from high concentration to low concentration means greater potential to low potential.
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