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Suppose that in addition to repairing your car, you can also spend money adverti

ID: 1169773 • Letter: S

Question

Suppose that in addition to repairing your car, you can also spend money advertising. If you repair your car for H hours and spend A dollars advertising, your benefit (the amount you receive when you sell your car) is B(H, A) = 220H H2 +2A. Both H and A are finely divisible. What is your benefit of repair hours when H = 4 and A = 100? What is your marginal benefit of advertising dollars at that choice? Suppose that in Calculus Problem #2 repair work costs $100 per hour and you have $1500 to allocate between repair work and advertising. Write the constrained optimization problem you face. What is your best choice of repair hours and advertis- ing? Interpret the condition that characterizes your best choice in terms of marginal benefits and marginal (opportunity) costs of repair work?

Explanation / Answer

Benefit, B = 220H - H2 + 2A

(1)

When H = 4, A = 100,

B = (220 x 4) - 16 + (2 x 100) = 880 - 16 + 200

B = 1,064

(2)

To calculate marginal benefit from advertising, let us increase A by 1 unit, from 100 to 101.

B (when A = 101) =  (220 x 4) - 16 + (2 x 101) = 880 - 16 + 202 = 1,066

So, marginal benefit = 1,066 - 1,064 = 2

Mathematically, marginal benefit from advertising is found by differentiating total benefit with respect to A:

MB = dB / dA = 2

(3)

Total cost, C = 100H + A

So, the optimization prblem is

Maximize B = 220H - H2 + 2A

Subject to C = 100H + A

100H + A <= 1500

A >= 0, H >= 0

(4)

The best (optimum) condition requires that

Marginal benefit, MB = Marginal Cost, MC

Or:

dB / dH = dC / dH

220 - 2H = 100

2H = 120

H = 60

So, Total repair hours = 60, repair cost = 60 x $4 = $240, Advertising cost = $(1500 - 240) = $1260

(5)

This condition implies that the slopes of total benefit and total cost curves are equal.

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