Suppose that in addition to repairing your car, you can also spend money adverti
ID: 1169773 • Letter: S
Question
Suppose that in addition to repairing your car, you can also spend money advertising. If you repair your car for H hours and spend A dollars advertising, your benefit (the amount you receive when you sell your car) is B(H, A) = 220H H2 +2A. Both H and A are finely divisible. What is your benefit of repair hours when H = 4 and A = 100? What is your marginal benefit of advertising dollars at that choice? Suppose that in Calculus Problem #2 repair work costs $100 per hour and you have $1500 to allocate between repair work and advertising. Write the constrained optimization problem you face. What is your best choice of repair hours and advertis- ing? Interpret the condition that characterizes your best choice in terms of marginal benefits and marginal (opportunity) costs of repair work?
Explanation / Answer
Benefit, B = 220H - H2 + 2A
(1)
When H = 4, A = 100,
B = (220 x 4) - 16 + (2 x 100) = 880 - 16 + 200
B = 1,064
(2)
To calculate marginal benefit from advertising, let us increase A by 1 unit, from 100 to 101.
B (when A = 101) = (220 x 4) - 16 + (2 x 101) = 880 - 16 + 202 = 1,066
So, marginal benefit = 1,066 - 1,064 = 2
Mathematically, marginal benefit from advertising is found by differentiating total benefit with respect to A:
MB = dB / dA = 2
(3)
Total cost, C = 100H + A
So, the optimization prblem is
Maximize B = 220H - H2 + 2A
Subject to C = 100H + A
100H + A <= 1500
A >= 0, H >= 0
(4)
The best (optimum) condition requires that
Marginal benefit, MB = Marginal Cost, MC
Or:
dB / dH = dC / dH
220 - 2H = 100
2H = 120
H = 60
So, Total repair hours = 60, repair cost = 60 x $4 = $240, Advertising cost = $(1500 - 240) = $1260
(5)
This condition implies that the slopes of total benefit and total cost curves are equal.
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