TEST PARAMETER UNITS TEST RESULT DETECTI LIMIT pH of water Electrical Conductivi

Question

TEST PARAMETER UNITS TEST RESULT DETECTI LIMIT pH of water Electrical Conductivity Total Dissolved Solids Magnesium (for SAR) Calcium (for SAR) Sodium (for SAR) Potassium by ICP Sodium Adsorption Ratio (SAR) Carbonate Bicarbonate PH micromhos/cm 836 mg/L meq/L meq/L meq/L mg/L con So 7.95 1 27 0.01 0.01 0.01 0.3 0.01 0.01 0.01 1.15 3. 33 3.81 6.8 meq/L meq/L mg/L mg/L meq/L 0.00 3.33 166 224 Not detected 0.01 Alkalinity (as CaCO3) Hardness as CaCO3 Residual Sodium Carbonate (RSC) What is the EC of the water sample in dS/m? Calculate the mg/L TDS of this water sample.

Explanation / Answer

Electrical conductivity (EC) of given sample is 836 micro-mhos/cm.

Now 1 mho= 1 Siemens

therefore, 836 micro-mhos/cm= 836 micro-siemens/cm.

and, 1 dS/m= 1000 micro-siemens/cm.

1micro-siemens/cm = 1/1000 dS/m

836 micro-siemens/cm = 836/1000dS/m

836 micro-mhos/cm = 836 micro-siemens/cm = 8.36dS/m

TDS (Total dissolved solids)= magesium, calcium, sodium and potassium.

magesium= 1.15meq/L= 12x1.15 = 13.8ppm

calcium= 3.33meq/L= 20x3.33 = 66.6ppm

sodium= 3.81meq/L = 23x3.81 = 87.63ppm

potassium=6.8mg/L

1ppm(Parts per million) =1mg/liter

magesium= 1.15meq/L= 12x1.15 = 13.8ppm = 13.8mg/L

calcium= 3.33meq/L= 20x3.33 = 66.6ppm= 66.6mg/L

sodium= 3.81meq/L = 23x3.81 = 87.63ppm= 87.63mg/L

potassium=6.8mg/L

TDS (Total dissolved solids)= magesium+calcium+sodium+potassium = 13.8+66.6+87.63+6.8=174.83mg/L

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