Questions are from The Practice of Statistics for Business and Economics, 3rd Ed
ID: 1197548 • Letter: Q
Question
Questions are from The Practice of Statistics for Business and Economics, 3rd Ed.
4.34 World Internet Usage. Approximately 23.6% of the world’s population uses the Internet (as of December 2008). Furthermore, a randomly chosen Internet user has the following probabilities of being from the given region of the world:
(a) What is the probability of a randomly chosen Internet user not being from one of the four regions explicitly listed in this table.
(b) What is the probability of a randomly chosen Internet user living in either Asia or Europe?
(c) What is the probability of a randomly chosen Internet user not living in North America?
Explanation / Answer
a) For the probability of a randomly chosen Internet user not being from one of the four regions explicitly listed in the table (P1) = 1 - [P(Asia) + P(Europe) + P(North America) + P(Latin America/Caribbean)]
P1 = 1 - [0.411 + 0.247 + 0.156 + 0.110]
P1 = 1 - 0.924
P1 = 0.076 or 7.6%
Therefore, the probability of a randomly chosen Internet user not being from one of the four regions explicitly listed in the table is 0.076 or 7.6%
b) For the probability of a randomly chosen Internet user living in either Asia or Europe (P2) = P(Asia) + P(Europe)
P2 = 0.411 + 0.247
P2 = 0.658 or 65.8%
Therefore, the probability of a randomly chosen Internet user living in either Asia or Europe is 0.658 or 65.8%.
c) For the probability of a randomly chosen Internet user not living in North America (P3) = 1 - P(North America)
P3 = 1 - 0.156
P3 = 0.844 or 84.4%
Therefore, the probability of a randomly chosen Internet user not living in North America is 0.844 or 84.4%.
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