Stackelberg Duopoly: Two firms both have the same constant marginal cost of $20
ID: 1204539 • Letter: S
Question
Stackelberg Duopoly:
Two firms both have the same constant marginal cost of $20 0 and zero fixed cost; market price P = 140 2(q1 + q2). Both firms choose outputs to compete.
(a) Find the subgame perfect equilibrium outcome of the Stackelberg Duopoly game with Firm 1 moving first. First, solve for the follower’s (Firm 2’s) best response function. Then solve for the leader’s optimal strategy.
(b) Find the Nash equilibrium of the Cournot duopoly under the same assumptions on costs and demand.
(c) Compare the two equilibria. Discuss the differences.
Explanation / Answer
(a) STACKELBERG
P = 140 – 2Q where Q = q1 + q2
P = 140 – 2q1 – 2q2
So,
Total revenue of firm 1, TR1 = P x q1 = 140q1 – 2q12 – 2q1q2
Total revenue of firm 2, TR2 = P x q2 = 140q2 – 2q1q2 – 2q22
So, Marginal revenue of firm 2, MR2 = dTR2 / dq2 = 140 – 2q1 – 4q2
MC2 = 20
Equating MR2 = MC2,
140 – 2q1 – 4q2 = 20
Or,
2q1 + 4q2 = 120
Dividing both sides by 2:
q1 + 2q2 = 60
Or, q2 = (60 – q1) /2 = 30 – 0.5q1 ..... (1)
This is firm 2’s response function. Substituting (1) in TR1:
TR1 = 140q1 – 2q12 – 2q1q2 = 140q1 – 2q12 – 2q1 (30 – 0.5q1)
= 140q1 – 2q12 – 60q1 + q12
= 80q1 – q12
So, MR1 = dTR1 / dq1 = 80 – 2q1
Equating MR1 = MC1 [Where MC1 = 20]
80 - 2q1 = 20
2q1 = 60
q1 = 30
therefore, q2 = 30 – 0.5q1 [From (1)]
= 30 – 0.5 x 30 = 15
Q = q1 + q2 = 30 + 15 = 45
P = 140 – 2Q = 140 – (2 x 45) = 140 - 90 = 50
(b) COURNOT
P = 140 – 2Q where Q = q1 + q2
P = 140 – 2q1 – 2q2
So,
Total revenue of firm 1, TR1 = P x q1 = 140q1 – 2q12 – 2q1q2
Total revenue of firm 2, TR2 = P x q2 = 140q2 – 2q1q2 – 2q22
So,
Marginal revenue of firm 1, MR1 = dTR1 / dq1 = 140 - 4q1 - 2q2
Equating with MC1:
140 - 4q1 - 2q2 = 20
4q1 + 2q2 = 120
2q1 + q2 = 60 ......(1) [Reaction function, firm 1]
Marginal revenue of firm 2, MR2 = dTR2 / dq2 = 140 – 2q1 – 4q2
MC2 = 20
Equating MR2 = MC2,
140 – 2q1 – 4q2 = 20
Or,
2q1 + 4q2 = 120
q1 + 2q2 = 60 .....(2) [Reaction function, firm 2]
Equilibrium is obtained by solving (1) & (2).
2q1 + q2 = 60 ......(1)
(2) x 2:
2q1 + 4q2 = 120 .....(3)
(3) - (1): 3q2 = 60
q2 = 20
q1 = 60 - 2q2 = 60 - (2 x 20) = 60 - 40 = 20
Q = q1 + q2 = 20 + 20 = 40
P = 140 - 2Q = 140 - (2 x 40) = 140 - 80 = 60
(c) Market quantity is higher in Stackelberg than under Cournot (45 > 40) and market price is lower under Stackelber than under Cournot (50 < 60).
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