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n C nitnfication D none of the above 1 Rain rosson avelves A detachmest B transp

ID: 121218 • Letter: N

Question

n C nitnfication D none of the above 1 Rain rosson avelves A detachmest B transport d. all of the abeve. $2 tn general, sol anion exchange capacity will as plf increases A increase B decrease C. remain the same D no relationship at all S3 A Sertilizer with 16-16-12 grade coatains about what pencestage of actual elemental potassium 03 54. Ifyou wanted to reduce the percentage sodium saturation from 30% to 9%inasodie sol with a CEC of20emol,kg. B. 12 how many g of Caso2H:0 would eed to react with 1 kg of this sod? A 30.86 B 20.19 C. 10.65 55. Ifyour soil test recommendation for N was 120 lbs per acre, and you have a yard that sa only 121 by 360 ft,tbe 56 lfyour sed test recommendation for N as 120 lbs per acre, and you havrayard thut is otly1ftbyk60 ft.the 57. A new Hummer on average travels 12 miles per gallon and if a gallon of fuel prodaces 20 e of Co The amount of 58. If a hectare C million kg sou) contains 3% organic matter and 29% of the organic mater is mineralized If the organic amount of N you will need will be hint: an acre is 43560 A. 120 Ib B. 60 b C 12 D. None of the above mount ofurea (46% N) you need will be A. 120 Ibs B261 lbs C 383 CO, emited ad you drve it for five years at 15,000 males per year wil be A. 125,000 Ibs B 200,000 Tbs C 180,000 s D none of the above matter eeatans SAN.the amount ofNmnerkre by this process uill be A 6kg B.kg C 600,000 kg D 1200 kg The weight ofa mont a dovendry weights ofa ial are 180 and 160 g. mpedehren!" of wee (%)nthe soud will be 9 A20% B.12.5% D Roll Tide your works for problems 61-65 neatly in the space provided in DETAIL section has 10 poiats. Use the following atomik weights H-1, C S 32, K-3, Ca-40, ifnecessary and circle your final answer. This -12, N-14,0-16, Na-23, Mg-34, A-27, P-31, 61 Assume 100 have a sed sample with the follow properties Cakult,dry belk des ity, and peresityr (Assume denty of-1gm, and partele densny 2 65 Eimh Value Water saturated weight 360 Oven-dry weight 6

Explanation / Answer

Mass of water (%)=

[(moist soil weight - oven dry soil weight) / moist soil weight] x 100

=[(180 - 160) / 180] x 100 = [20 / 180] x 100= [100/9]= 11.1%

So, the right answer option is option C or 11.1%