H3C-CO-COO- + CoA + NAD+ H3C-CO-S-CoA + NADH H+ + CO2 A. What is happening to th
ID: 123803 • Letter: H
Question
H3C-CO-COO- + CoA + NAD+ H3C-CO-S-CoA + NADH H+ + CO2 A. What is happening to the Carbon containing reactant molecule turning into CO2? How do you know? (5-1; U) (1.5 pts) B. In reference to the Carbon containing reactant molecule turning into CO2, is this an anabolic or catabolic reaction? How can you tell? (5-1; U) (1.5 pts) 3. An antibiotic was discovered to inhibit citrate synthase. How many ATP would be produced per glucose after the addition of the antibiotic? Show all work. (5-13,16; E) (2 pts) 4. An antibiotic was discovered to inhibit succinate dehydrogenase in the electron transport chain. How many ATP would be produced per glucose after the addition of the antibiotic? Show all work. (5-15,16; E) (2 pts)
Explanation / Answer
Glucose is a 6 carbon molecule during the process of glycolysis it can splits into 2 molecules of PYRUVATE in the cytosol. Then each pyruvate can contain 3 molecules of carbon. After completion of glycolysis pyruvate had 2 pathways.
Anaerobic pathway: In the absence of oxygen the pyruvate molecule can undergoes into fermentation either lactic acid fermentation or alcohol fermentation.
Aerobic pathway: In the presence of oxygen pyruvate is converted to acetyl-CoA and later it enters into the Kerb cycle where large (most) of ATP molecules is generated.
Glucose CO2 Elimination through PDH complex:
Under the aerobic condition pyruvate is transported into mitochondria matrix. In the presence of oxygen the pyruvate molecule is oxidatively decarboxylated by the pyruvate dehydrogenase complex and converted into acetyl co-A.
The overall reaction catalyzed by PDH is as follows:
Pyruvate + Co-A-SH + NAD+ CO2 + acetyl-Co-A + NADH + H+
It is a catabolic reaction because in this reaction the 3 carbon molecule breaks down into 2 carbon molecule.
The breakdown of glucose can produce ATP in following steps.
STEP 1: Glycolysis 6 ATP Produced.
STEP 2: Oxidative posporilation 6 ATP Produced.
STEP 3: Krebs cycle or citric acid cycle 24 ATP Produced.
An antibiotic inhibit citrate synthase:
14 ATP produced
Explanation:
In glycolysis 2 NADH (2 X 3= 6 ATP), 1SLP (2 ATP) is produced so the net ATP is 8 ATP.
In oxidative posporilation 6 ATP is produced 2 NADH (2 X 3= 6 ATP)
Net ATP = 8 + 6 = 14 ATP
An antibiotic inhibit succinate dehydrogenase:
26 ATP produced
Explanation:
In glycolysis 2 NADH (2 X 3= 6 ATP), 1SLP (2 ATP) is produced so the net ATP is 8 ATP.
In oxidative posporilation 6 ATP is produced 2 NADH (2 X 3= 6 ATP)
In TCA cycle during the IDH and Alfa KGDH reactions each round 1 NADH produced at each center. Per 2 rounds of cycle 4 NADH is generated, so 4 X 3 = 12 ATP are produced.
Net ATP = 8 + 6 + 12= 26 ATP
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