Fill in the table and solve the following questions (Using D-method). Given Fx m
ID: 1258150 • Letter: F
Question
Fill in the table and solve the following questions (Using D-method).
Given
Fx method
d-method
Class Interval
f
X
X2
cf
fX
fX2
d
fd
d2
fd2
30-34
3
-2
35-39
7
-1
40-44
11
0
45-49
22
1
50-54
40
2
Total
Mean
Median
Mode
Range
Variance
Standard deviation
Quartile 1st
Fill in the table and solve the following questions (Using D-method).
Given
Fx method
d-method
Class Interval
f
X
X2
cf
fX
fX2
d
fd
d2
fd2
2 - 12
5
7
-1
12 - 22
7
17
0
22 - 32
5
27
1
32 - 42
3
37
2
Total
Mean
Median
Mode
Range
Variance
Standard deviation
Quartile 1st
Given
Fx method
d-method
Class Interval
f
X
X2
cf
fX
fX2
d
fd
d2
fd2
30-34
3
-2
35-39
7
-1
40-44
11
0
45-49
22
1
50-54
40
2
Total
Explanation / Answer
Mean = sum(fX)/sumf = 3931/83 = 47.36
Median = L + ((n/2-F)/f)*i
L = lower boundary of class median
i = class width
n = sum of frequency
F = cumlative frequency before class medium
f = frequency of class median
n/2 = 41.5 which is 3rd median class i.e. 40-44
f = 11 F = 10 i=5 L = 39.5
median = 39.5 + (41.5-10)/11 * 5 = 39.5+14.3 = 53.8
1st quartile = LQ1 + ((n/4-F)/fQ1)*i
L = lower boundary of class 1st quartile
i = class width
n = sum of frequency
F = cumlative frequency before class 1st quartile
f = frequency of class 1st quartile
n/4 = 41.5 which is 3rd median class i.e. 40-44
f = 11 F = 10 i=5 L = 39.5
median = 20.75 + (20.75-3)/7 * 5 = 20.75+12.67 = 33.42
mode = 39.5 + 18/(40+18)*5 = 39.5 + 1.55 = 41.05
Variance = (sum of fX^2 - (sum of fX)^2/n)/(n-1) = (188817 - 3931^2/83)/82 = 32.185
Std. deviation = sqrt(variance) = 5.67
range = 54-30 = 24
Class Interval f X X^2 Cf fX fX^2 d fd d^2 fd^2 30-34 3 32 1024 3 96 3072 -2 -6 4 12 35-39 7 37 1369 10 259 9583 -1 -7 1 7 40-44 11 42 1764 21 462 19404 0 0 0 0 45-49 22 47 2209 43 1034 48598 1 22 1 22 50-54 40 52 2704 83 2080 108160 2 80 4 160 Sum 83 210 9070 3931 188817 89 10 201Related Questions
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